Question

The sum of three consecutive numbers is $36$. Find the numbers.

• A. 12
• B. 11
• C. 13
• D. 10

Answer 1

Answer: (A), (C), (D)

The correct options are A ($12$)
C ($13$)
D($10$)

Let the first number be $a$.

So the three consecutive numbers will be $a,a+1,a+2$.

Given condition: $\text{a +a +1 +a +2 = 36}$

$\Rightarrow$$\text{3a +3 = 36}$

$\Rightarrow$ $\text{3a = 36 -3 = 33}$

$\Rightarrow$$a=\frac{33}{3}=11$

So, the three consecutive numbers will be $11,12,13$.