Question

The sum of three consecutive numbers is $39$. What are the numbers?

Answer 1

Let the smallest number be ‘$x$’.

Since we are considering three consecutive numbers, the other two numbers will be $x+1$ and $x+2$.

So, $x+(x+1)+(x+2)=39$
⇒ $3x+3=39$
⇒ $3x+3-3=39-3$
⇒ $3x=36$
⇒ $x=\frac{36}{3}$
⇒ $x=12$

Thus, the three consecutive numbers are $12$, $12+1$, and $12+2$.
So, $12$, $13$, and $14$ are the required numbers.