Question

The sum of three consecutive terms of an $AP$ is $72$. Then, the middle term is

• A. $18$
• B. $24$
• C. $36$
• D. $48$

Answer 1

The correct option is B $24$

Let the three terms be $a-d,a,a+d$

A/Q $a-d+a+a+d=723a=72\Rightarrow a=\frac{72}{3}=24$

$\therefore$ Mid term $=24$