CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The sum of three expressions is x2+y2+z2. If two of them are 4x25y2+z2 and 3x2+4y2+2z2, find the third expression.

A
2x2+2z2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2y2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2x2+2y2z2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2y22z2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 2y22z2
Let the third expression be a then,
a+(4x25y2+z2)+(3x2+4y2+2z2)=x2+y2+z2
a+(x2y2+3z2)=(x2+y2+z2)
a=(x2+y2+z2)x2+y23z2
a=2y22z2

Hence, option D is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Addition and Subtraction of Algebraic Expression
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon