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Question

The sum of three expressions is x2+y2+z2. If two of them are 4x25y2+z2 and 3x2+4y2+2z2, find the third expression.

A
2x2+2z2
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B
2y2
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C
2x2+2y2z2
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D
2y22z2
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Solution

The correct option is D 2y22z2
Let the third expression be a then,
a+(4x25y2+z2)+(3x2+4y2+2z2)=x2+y2+z2
a+(x2y2+3z2)=(x2+y2+z2)
a=(x2+y2+z2)x2+y23z2
a=2y22z2

Hence, option D is correct.

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