wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The sum of three non-zero prime numbers is 100. One of them exceeds the other by 36. Find the largest number.

A
73
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
91
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
67
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
57
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 67
If the sum of 3 prime numbers is even, then one of the numbers must be 2.
Let the second number be x.
So, the numbers are x, (x+36) and 2.
Then as per the given condition,
x+(x+36)+2=100
2x+38=100
2x=62
x=31
So, the number are 2, 31 and 67.
Hence, the largest number is 67.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Primes and Composite Numbers
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon