The sum of three numbers in AP is 3 and their product is -35. find the numbers.
Let (x-d), x, (x+d) be in AP Then x-d+x+x+d = 3 x = 1 (x-d) x(x+d) = - 35 (1-d)1(1+d) = - 35 1 - d.d = -35 d = 6 (1-6), 1, (1+6) -5, 1, 7