Question

The sum of three numbers in AP is -3, and their product is 8. Find the numbers.

• A. -4, -1, 2
• B. 3, 2, 1
• C. 5, 6, 7
• D. 8, 12, 16

Answer 1

The correct option is A -4, -1, 2

Let the numbers be a-d,a,a+d
a-d+ a+ a+d= -3
a=-1
(a-d) (a) (a+d) =8
$d^2=9\Rightarrow d=3$
Thus the numbers are -4,-1 and 2