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Question

The sum of three numbers is 123. If the ratio between first and second number is 2:5 and that of between second and third is 3:4 then find the difference between second and third number.


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Solution

Let the three numbers be a, b, and c.

Given that

a:b=2:5

We can also write it as

a:b=6:15

Also second given condition is

b:c=3:4

We can also write it as

b:c=15:20

Hence from above equations

a:b:c=6:15:20

Let us assume that a=6x, b=15x and c=20x.

Given sum of all the three numbers = 123

On adding all the three numbers we get,

a+b+c=123

6x+15x+20x=123

41x=123

x=3

Hence a=18, b=45 and c=60.

The difference between the second and the third number is 6045=15.

Hence, the difference between the second and the third number is 15.


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