Question

The sum of three numbers whose ratios are10/3:21/5:25/8 is 4917.find the numbers?

Answer 1

10/3x+21/5x+49/8x=4917.........(1)
x[10/3+21/5+49/8]=4917
x[10*5*8+21*3*8+49*3*5]
= 4917*3*5*8
x[400+504+734]=4917*3*5*8
x[1639]=590040
x=590040/1639=360
x=360.
put the value of x into equation (1) and we get,
10/3x=1200,
21/5x=1512,
49/8x=2205.
we get the three numbers are 1200, 1512, and 2205.