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Question

The sum of three terms of AP is 21 and Minimum value of the product of the first and the third terms

A
30
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B
494
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C
594
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D
48
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Solution

The correct option is D 48
Let x,x+1,x+2 are three terms which are in A.P
So, according to the question,
x+x+1+x+2=21
3x+3=21
3x=18
x=6
The three numbers are 6,7,8 which are in A.P
Here, first tem is 6 and third term is 8
Required product =6×8=48

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