The sum of three times a number and 5 added to that number is 41. Find the number.

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Solution

Let $x$ be the number.
$\Rightarrow 3 x + 5 = 41$ (given)
$\Rightarrow 3 x = 41 - 5 = 36$
$\Rightarrow x = \frac{36}{3} = 12$
$∴$ The number is $12$

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The sum of three times a number and 5 added to that number is 41. Find the number.

Let x be the number.⇒3x+5=41(given)⇒3x=41−5=36⇒x=363=12∴ The number is 12

Let $x$ be the number.
$\Rightarrow 3 x + 5 = 41$ (given)
$\Rightarrow 3 x = 41 - 5 = 36$
$\Rightarrow x = \frac{36}{3} = 12$
$∴$ The number is $12$