Question

The sum of three times a number and four times its reciprocal can be written as:

• A. $\frac{(3x^2+4)}{x}$
• B. $\frac{\left(3x\right)}{4}$
• C. $\frac{(3x+4)}{x^2}$
• D. $\frac{(4x^2+3)}{2x}$

Answer 1

The correct option is A

$\frac{(3x^2+4)}{x}$

Let a number be 'x' and then its reciprocal will be $\frac{1}{x}$

Three times this number $=3x$

And four times the reciprocal of the same number $=\frac{4}{x}$

It's sum $=3x+\left(\frac{4}{x}\right)$

$\therefore$ The sum is: $\frac{(3x^2+4)}{x}$