Question 89
The sum of two consecutive multiples of 2 is 18. Find the numbers.
Let the two consecutive multiples of 2 be 2x and 2x+2.
According to the question,
2x + 2x + 2 = 18
⇒4x+2=18⇒4x=18−2 [transposing 2 to RHS]⇒4x=16⇒4x4=164 [dividing both sides by 2]⇒x=4
Hence, the required numbers are 2x = 2×4=8 and 2x+2 = 2×4+2=10.