The sum of two consecutive whole numbers is $12$ . If the smaller number is n, which is the correct equation?

2 n = 12

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n + n - 1 = 12

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2 n - n = 12

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n + n + 1 = 12

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Solution

The correct option is B $n + n + 1 = 12$
Smaller number= $n$ , its consecutive number will be $n + 1$ .
As per given condition , there addition is $12$
$∴$ $n + n + 1 = 12$ .

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