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Question

The sum of two-digit numbers and the number obtained by reversing the order of the digit is 121. Find the number, if the digits differ by 3.

A
47 or 74
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B
36 or 63
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C
67 or 76
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D
94 or 49
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Solution

The correct option is A 47 or 74
Let the two digit number be 10x+y
On reversing its digits, we get the number 10y+x
Given, (10x+y)+(10y+x)=121
11x+11y=121
=> x+y=11 --- (1)
Given, xy=3 -- (2)
Adding (1) and (2), we get
2x=14 => x=7
Substituting x=7 in the equation (2), we get 7y=3y=4
Hence, the number is 74 or 47


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