Question

The sum of two natural numbers is $28$ and their product is $192$. Find the numbers.

Answer 1

suppose two natural number is $x$ and $y$

$\begin{array}{c}x+y=28\\ x=28-y\end{array}$

product of the number

$x\times y=192$

put the value of $x$

$\begin{array}{c}\left(28-y\right)\times y=192\\ 28y-y^2-192=0\\ y^2-28y+192=0\\ y\left(y-16\right)-12\left(y-16\right)=0\\ \left(y-16\right)\left(y-12\right)\\ y=12\\ or\\ y=16\end{array}$