The sum of two numbers is 100 and their difference is 40. Find the numbers.
70, 30
let the number be a & b
a + b = 100
a - b = 40
adding we get
(a + b) + (a - b) = 100 + 40 [x + (y + z) = x + y + z]
a + b + a - b = 140
2a = 140
a = 70
Subtracting we get
(a + b) - (a - b) = 100 - 40
a + b - a + b = 60 [x - (y - z) = x - y + z]
2b = 60
b = 30