Question

The sum of two numbers is $\frac{-1}{3}.$ If one of the numbers is $\frac{-12}{3},$ find the other.

Answer 1

$$\begin{gathered} \mathrm{It}\mathrm{is}\mathrm{given}\mathrm{that}the\mathrm{sum}\mathrm{of}\mathrm{two}\mathrm{numbers}\mathrm{is}\frac{-1}{3},\mathrm{where}\mathrm{one}\mathrm{of}\mathrm{the}\mathrm{number}s\mathrm{is}\frac{-12}{3}. \\ \mathrm{Let}\mathrm{the}\mathrm{other}\mathrm{number}be\mathit{}x\mathit{.} \\ \therefore x+\frac{-12}{3}=\frac{-1}{3} \\ \Rightarrow x=\frac{-1}{3}-\frac{-12}{3} \\ \Rightarrow x=\frac{-1-(-12)}{3}=\frac{-1+12}{3}=\frac{11}{3} \end{gathered}$$