The correct option is A 5 and 3
Let the numbers be x and y
⇒x+y=8 .....(1) and
x+y=4(x−y) (Assuming x > y)
⇒3x−5y=0 ......(2)
On multiplying equation (1) by 5, we get
5x+5y=40 ......(3)
On adding equations (2) and (3), we get
8x=40
⇒x=5
On substituting x=5 in equation (1), we get
5+y=8
⇒y=3
Therefore, the numbers are 5 and 3.