Question

The sum of two numbers is $80$ and the first number is $20$ more than the second. Find the numbers.

Answer 1

Suppose the first number is $x$ and second number is $y$
According to question:
$x+y=\mathrm{80......}\left(1\right)$
and $x=y+20$
$\Rightarrow$ $x-y=\mathrm{20.......}\left(2\right)$
Adding equation $\left(1\right)$ and $\left(2\right)$
$x+y=80$
$x-y=20$
-------------------
$2x=100$
$x=50$
Putting value of $x$ in equation $\left(1\right)$
$50+y=80$
$\Rightarrow$ $y=80-50$
$\Rightarrow$ $y=30$
The required numbers are $50$ and $30$.