Question

The sum of two numbers is $80$ and the greater number exceeds twice the smaller by $11$. Find the numbers.

Answer 1

Let larger number is $x$.

And Smaller number is $y$

Now,

$x+y=\mathrm{80...........}\left(1\right)$

$x=2y+\mathrm{11............}\left(2\right)$

From $\left(2\right)$

$\begin{array}{c}x-2y=11\\ \underset{–}{x+y=80}\\ -3y=-69\end{array}$

$y=23$

For $x$:

$x=80-23=57$

Thus,

$x=57$ & $y=23$