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Question

The sum of two numbers is 95. If one exceeds the other by 15, then the smaller of the two is

(a) 40

(b) 35

(c) 45

(d) 55

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Solution

Let first number = x

Then second number = x + 15

x + x + 15 = 95 2x = 95 -15 = 80

x=802=40

Smaller number = 40


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