Question

The sum of two numbers is $\frac{13}{6}$.

An even number of AMs are being inserted between them. The sum of means inserted exceeds the number of means by one. Find the number of AMs inserted.

Or

Find the sum of infinite series. $\frac{1}{3}+\frac{1}{5^2}+\frac{1}{3^2}+\frac{1}{5^4}+\frac{1}{3^3}+\frac{1}{5^6}+.......$

Answer 1

Number of Ams = 12

Or

$\frac{13}{24}$