Question

The sum of two rational numbers is $\frac{-3}{8}$. If one of them is $\frac{3}{16}$, find the other.

Answer 1

$\begin{array}{l}\\ \text{Let the other number be}\mathit{\text{x.}}\\ \\ \frac{3}{16}+x=\frac{-3}{8}\\ \\ =>x=\frac{-3}{8}-\frac{3}{16}\\ \mathrm{L}.\mathrm{C}.\mathrm{M}.\mathrm{of}8\mathrm{and}16\mathrm{is}16.\\ =>x=\frac{-6-3}{16}\\ \\ =>x=\frac{-9}{16}\\ \end{array}$