The sum of $x^{4} - x y + 2 y^{2}$ and $- x^{4} + x y + 2 y^{2}$ is

Monomial and polynomial in

y

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Binomial and Polynomial

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Trinomial and polynomial

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Monomial and polynomial in

x

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Solution

The correct option is A Monomial and polynomial in $y$
Required sum $= x^{4} - x y + 2 y^{2} + - x^{4} + x y + 2 y^{2}$
$= x^{4} - x y + 2 y^{2} - x^{4} + x y + 2 y^{2}$
$= [x^{4} +) - x^{4})] + (- x y + x y) + (2 y^{2} + 2 y^{2})$
$= 0 + 0 + 4 y^{2} = 4 y^{2}$
$4 y^{2}$ is a monomial and polynomial in $y$

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Similar questions

Question 8

Out of the four options, only one is correct. Write the correct answer.

The sum of $x^{4} - x y + 2 y^{2}$ and $- x^{4} + x y + 2 y^{2}$ is

(a) monomial and polynomial in y
(b) binomial and polynomial
(c) trinomial and polynomial
(d) monomial and polynomial in x

The sum of $x^{4} - x y + 2 y^{2}$ and $- x^{4} + x y + 2 y^{2}$ is

x^{2} - x y - 2 y^{2}

x^{2} + 3 x y + 2 y^{2}

x - 2 y

2 x - y

2 x^{2} - x y + 2 y^{2}

x - x^{3}

y + y^{2} + 4

1 + x

x - x y

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