The sum -k-1201-2-3- k is

∑_k =1^20(1+2 + 3+...+ k) = ∑_k =1^20k(k+1)2 = 12∑_k =1^20( k^2 + k) = 12 [ 20× 21 × 416+ 20×212 ] = 12 [2870 +210] = 1540 nbsp; ...

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Sigma n2

The sum ∑k=12...

Question

The sum $20 \sum k = 1 (1 + 2 + 3 + . . . + k)$ is

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