The sun radiates electromagnetic energy at the rate of 3-9- 10 26 W- Its radius is 6-96- 10 8 m- The intensity of sunlight at the solar surface will be in W-m2 -

The correct option is A 6.4× 10 ^ 7 Intensity at solar surface=Power per unit area= WA=W4π r^2=3.9× 10^264π (6.96× 10^8)^2=6.4× 10^7W/m^2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Dimensional Analysis

The sun radia...

Question

The sun radiates electromagnetic energy at the rate of $3.9 \times 10^{26} W$ . Its radius is $6.96 \times 10^{8} m$ . The intensity of sunlight at the solar surface will be (in $W / m^{2}$ ) :

6.4 \times 10^{7}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2.8 \times 10^{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.2 \times 10^{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5.6 \times 10^{7}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $6.4 \times 10^{7}$
Intensity at solar surface=Power per unit area= $\frac{W}{A} = \frac{W}{4 π r^{2}} = \frac{3.9 \times 10^{26}}{4 π (6.96 \times 10^{8})^{2}} = 6.4 \times 10^{7} W / m^{2}$

Suggest Corrections

Similar questions

Q. The sun radiates electromagnetic energy at the rate of

3.9 \times 10^{26} W

. Its radius is

6.96 \times 10^{8} m .

The intensity of sun light at the solar surface will be in

(\frac{W}{m^{2}})

Q. The sun radiates electromagnetic energy at the rate of

3.9 \times 10^{26} W

. Its radius is

6.96 \times 10^{8} m

. If the distance from the sun to the earth is

1.5 \times 10^{11} m

, then the intensity of sunlight on earth's surface will be (in

W / m^{2}

Each square metre of sun’s surface radiates energy at the rate of $6.27 \times 10^{7} W m^{- 2}$ . Assuming that Stefan’s law applies to the radiation, the temperature of sun’s surface is (Stefan’s constant $σ = 5.7 \times 10^{7} W m^{- 2} K^{- 4}$ )

Q. The sun delivers

10^{5} {W/m}^{2}

electromagnetic flux to the earth's surface. The total power that is incident on the roof of dimensions

(20 \times 20) m^{2}

will be

Q. The earth receives at its surface radiation from the sun at the rate of

1400 w / m^{2}

. The distance of the centre of the sun from the surface of the earth is

1.5 \times 10^{11} m

and the radius of the sun is

7 \times 10^{8} m

. Treating sun as a black body, it follows from the above data that its surface temperature is

Join BYJU'S Learning Program

The sun radiates electromagnetic energy at the rate of 3.9×1026W. Its radius is 6.96×108m. The intensity of sunlight at the solar surface will be (in W/m2) :

The correct option is A 6.4×107Intensity at solar surface=Power per unit area=WA=W4πr2=3.9×10264π(6.96×108)2=6.4×107W/m2

The sun radiates electromagnetic energy at the rate of $3.9 \times 10^{26} W$ . Its radius is $6.96 \times 10^{8} m$ . The intensity of sunlight at the solar surface will be (in $W / m^{2}$ ) :

The correct option is A $6.4 \times 10^{7}$
Intensity at solar surface=Power per unit area= $\frac{W}{A} = \frac{W}{4 π r^{2}} = \frac{3.9 \times 10^{26}}{4 π (6.96 \times 10^{8})^{2}} = 6.4 \times 10^{7} W / m^{2}$