Question

The superelevation needed on a horizontal circular curves of 150 m radius for a design speed of 60 kmph with a coefficient of friction 0.15 is

Answer 1

Design of superelevation:

$e=\frac{{\left(0.75V\right)}^2}{gR}$

$e=\frac{{(0.75\times 60\times 0.278)}^2}{9.81\times 150}$

$e=0.1062>0.07$
Hence provide 0.07