The supply voltage to an opamp is +-15volts. The opamp is connected as an inverting amplifier of gain -20. The output voltage for an input voltage of 20mV is:

-400 mV

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

+ 400 mV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-200 mV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

+200 mV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A -400 mV
Voltage gain and output voltage are related by the formula $A_{v} = \frac{o u t p u t v o l t a g e}{i n p u t v o l t a g e}$ . Substituting the value of input voltage, we get, output voltage = - 20 x 20mV = -400 mV

Suggest Corrections

Similar questions

2 k Ω

4 V

100

1 k Ω

Assuming ideal opamp, the RMS voltage (in mV) in the output $V_{0}$ only due to the 230 V, 50 Hz interference is (up to one decimal place)

400 m V

200

μ A

Join BYJU'S Learning Program