The surd having radicand $9$ and order $3$ is.

\sqrt[9]{3}

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\sqrt[3]{27}

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\sqrt[3]{9}

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\sqrt[3]{81}

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Solution

The correct option is C $\sqrt[3]{9}$
Given that,

Radicand $= 9$
Order $= 3$

$\Rightarrow$ Number is $9^{\frac{1}{3}}$

Surd is $\sqrt[3]{9}$

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