The surface area of the floor of a room is 30m2 and the walls are 3m high. If the room temperature is 27∘C and pressure is 1 atm, then find the mass of the air inside the room
[Given: Molecular weight of air = 29, 1 atm = 1.013 ×105 Pa]
A
105.85 kg
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B
29 kg
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C
74.37 kg
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D
135.35 kg
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Solution
The correct option is A 105.85 kg PV = nRT (1.013×105)(30×3)=no.ofmolesn×8.31×Kelvin(27+278) n=3.65×103moles
Mass of air inside =nM=3.65×103×29g