The surface area of the frustum cone is given its base radius, R = 4 cm and top radius, r = 2 cm. The height of the cone is 4 cm. Find the slant height of the cone.

\sqrt{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 \sqrt{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

24 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 \sqrt{5}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $2 \sqrt{5}$ cm
Slant height of a cone = $\sqrt{(R - r)^{2} + h^{2}}$
= $\sqrt{(4 - 2)^{2} + 4^{2}}$
= $\sqrt{(2)^{2} + 16}$
= $\sqrt{20}$
= $2 \sqrt{5}$ cm

Suggest Corrections

Similar questions

297 c m^{2}

2

5

π = 3

A cone of radius 3 cm and slant height 5 cm has curved surface area of ___ $c m^{2}$ .

A right circular cone with radius $5 c m$ and slant height $13 c m$ is given. Find the total surface area of the cone.

Join BYJU'S Learning Program