The surface charge density of a sphere of radius $r$ , is $σ$ . It is placed at a point $A$ . The electric field intensity at $B$ due to this sphere is $E$ . Another charge sphere of radius $2 r$ is placed at $B$ . If the intensity at the centre of $A$ and $B$ is $E / 2$ , then the surface charge density of $B$ is ?

2 E ϵ_{o}

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4 E ϵ_{o}

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E ϵ_{o}

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3 E ϵ_{o}

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Solution

The correct option is A $2 E ϵ_{o}$

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The surface charge density of a sphere of radius r, is σ. It is placed at a point A. The electric field intensity at B due to this sphere is E. Another charge sphere of radius 2r is placed at B. If the intensity at the centre of A and B is E/2, then the surface charge density of B is ?

The correct option is A 2Eϵo

The correct option is A $2 E ϵ_{o}$