Question

The surface charge density on a copper sphere is $\sigma$. So the intensity of electric field on its surface will be:

• A. $\sigma$
• B. $\frac{\sigma }{2}$
• C. $\frac{\sigma }{2\epsilon o}$
• D. $\frac{\sigma }{\epsilon o}$

Answer 1

The correct option is D $\frac{\sigma }{\epsilon o}$

The surface charge density on a copper sphere is $\sigma$

therefore$,$ the intensity of electric field on its surface will be$-$ $\frac{\sigma }{{\in }_0}$

Hence,

option $\left(D\right)$ is correct answer.