Question

The surface energy of liquid film on a ring of area $0.15m^2$ is (Surface tension of liquid $5N{m}^{-1}$)

• A. $0.75J$
• B. $1.5J$
• C. $2.25J$
• D. $3.0J$

Answer 1

Answer: (B)

$1.5J$

As we know,

Surface energy = $T\ast A=5\ast 2\ast \left(0.15\right)=1.5J$