Question

The surface of a globe is 11/23 m², find its diameter.

Answer 1

Dear student
$$\begin{gathered} Surfaceareaofglobe=\frac{11}{23}{m}^2 \\ \Rightarrow 4{\mathrm{\pi r}}^2=\frac{11}{23} \\ \Rightarrow {\mathrm{r}}^2=\frac{11}{23}\times \frac{1}{4\mathrm{\pi }} \\ \Rightarrow {\mathrm{r}}^2=\frac{11}{23}\times \frac{7}{4\times 22} \\ \Rightarrow {\mathrm{r}}^2=\frac{7}{184} \\ \Rightarrow {\mathrm{r}}^2=0.0380 \\ \Rightarrow \mathrm{r}=\sqrt{0.0380} \\ \Rightarrow \mathrm{r}=0.195\mathrm{m} \\ \mathrm{So},\mathrm{diameter}\mathrm{of}\mathrm{glope}=2\mathrm{r}=2\times 0.195=0.39\mathrm{m}=0.4\mathrm{m}\left(\mathrm{approx}\right) \end{gathered}$$
Regards