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Derivation of Position-Velocity Relation by Graphical Method

The surface t...

Question

The surface temperature of the sun which has maximum energy emission at 500 nm is 6000 K. The temperature of star which has maximum energy emission at 400 nm will be.

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Solution

We know that-

$λ T = c o n s t a n t$

$⟹ λ_{2} T_{2} = λ_{1} T_{1}$

$⟹ T_{2} = \frac{λ_{1} T_{1}}{λ_{2}}$

$T_{2} = \frac{500 \times 6000}{400}$

$⟹ T_{2} = 7500 K$

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Derivation of Position-Velocity Relation by Graphical Method

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