The surface tension of a liquid is 5 N/m. If a thin film of the area 0.02 $m^{2}$ is formed on a loop, then its surface energy will be

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Solution

The correct option is C

$W = T \times △ A = 5 \times 2 \times (0.02)$

$= 2 \times 10^{- 1}$ J

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The surface tension of a liquid is 5 N/m. If a thin film of the area 0.02 m2is formed on a loop, then its surface energy will be?
//in One of the byju's video they derived that
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then what is happening in the question
Surface tension is already given then why it is messing up with area and asking for surface energy ?

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The surface tension of a liquid is 5 N/m. If a thin film of the area 0.02 m2is formed on a loop, then its surface energy will be

The correct option is C W=T×△A=5×2×(0.02) =2×10−1J

The surface tension of a liquid is 5 N/m. If a thin film of the area 0.02 $m^{2}$ is formed on a loop, then its surface energy will be

The correct option is C

$W = T \times △ A = 5 \times 2 \times (0.02)$

$= 2 \times 10^{- 1}$ J