The surface tension of a soap solution is 0.05 Nm^-1. How much work is done to produce a soap bubble of radius 0.03 m?

1.5 x 10^-2J

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2.1 x 10^-3J

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1.1 x 10^-3J

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1.8 x 10^-2J

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Solution

The correct option is A
1.5 x 10^-2J

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Similar questions

0.05 N m^{- 1}

0.03 m

10 cm

= 0.03 N/m

10 c m

0.03 N / m

10 c m

\frac{3}{100} N / m

0.2 m

60 \times 10^{- 3} N / m

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