The surface tension of soap solution is $0.05$ $N m^{- 1}$ . If the diameter of the soap bubble is $4 c m$ . The excess pressure inside the soap bubble over that of outside is .............. Pascal:

10

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Solution

The correct option is D $10$
Excess pressure = $Δ P = \frac{4 T}{R}$
$Δ P = \frac{4 \times (0.05)}{4 / 2 \times 10^{- 2}}$
$Δ P = 10 P a$
So, excess pressure is 10 Pa

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The surface tension of soap solution is 0.05 Nm−1. If the diameter of the soap bubble is 4 cm. The excess pressure inside the soap bubble over that of outside is .............. Pascal:

The correct option is D 10Excess pressure = ΔP=4TRΔP=4×(0.05)4/2×10−2ΔP=10PaSo, excess pressure is 10 Pa

The surface tension of soap solution is $0.05$ $N m^{- 1}$ . If the diameter of the soap bubble is $4 c m$ . The excess pressure inside the soap bubble over that of outside is .............. Pascal:

The correct option is D $10$
Excess pressure = $Δ P = \frac{4 T}{R}$
$Δ P = \frac{4 \times (0.05)}{4 / 2 \times 10^{- 2}}$
$Δ P = 10 P a$
So, excess pressure is 10 Pa