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Standard VIII

Physics

Viscosity

The surface t...

Question

The surface tension of water is $7 \times 10^{- 2} N / m^{2}$ and its angle of contact with glass is zero. The rise of water in a capillary tube of diameter $0.5 m m$ is _________.

10 c m

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8 c m

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5.7 c m

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4 c m

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Solution

The correct option is C $5.7 c m$
The rise in the tube is given as,

$h = \frac{2 T cos θ}{r ρ g}$

$= \frac{2 \times 7 \times 10^{- 2} cos 0^{\circ}}{0.25 \times 10^{- 3} \times 1 \times 10^{3} \times 9.8}$

$= 5.71 \times 10^{- 2} m$

$= 5.71 c m$

Thus, the rise in the tube is $5.71 c m$ .

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The surface tension of water is 7×10−2N/m2 and its angle of contact with glass is zero. The rise of water in a capillary tube of diameter 0.5mm is _________.

The correct option is C 5.7cmThe rise in the tube is given as, h=2Tcosθrρg =2×7×10−2cos0∘0.25×10−3×1×103×9.8 =5.71×10−2m =5.71cm Thus, the rise in the tube is 5.71cm.

The surface tension of water is $7 \times 10^{- 2} N / m^{2}$ and its angle of contact with glass is zero. The rise of water in a capillary tube of diameter $0.5 m m$ is _________.

The correct option is C $5.7 c m$
The rise in the tube is given as,

$h = \frac{2 T cos θ}{r ρ g}$

$= \frac{2 \times 7 \times 10^{- 2} cos 0^{\circ}}{0.25 \times 10^{- 3} \times 1 \times 10^{3} \times 9.8}$

$= 5.71 \times 10^{- 2} m$

$= 5.71 c m$

Thus, the rise in the tube is $5.71 c m$ .