The surface tension of water is T. The weight (W)of water supported by surface tension in capillary tube of radius R is:

T .4 π R^{2}

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T .2 π R

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T . R

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T / 2 π R

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Solution

The correct option is B $T .2 π R$
Weight of water supported by surface tension in capillary tube of radius R is
$T \times 2 Π R$
Hence, $T \times 2 Π R$ is force by which weight of water is supported in capillary rise

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