The switch has been in position 1 for a long time and abruptly changes to position 2 at t = 0.
If time t is in seconds, the capacitor voltage VC (in volts) for t > 0 is given by
A
4(1−6e−t/0.5)
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B
10−6e−t/0.5
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C
4(1−6e−t/0.6)
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D
10−6e−t/0.6
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Solution
The correct option is D10−6e−t/0.6 at t=0−, Switch is at position 1
where, VC(0−)=10×22+3=4V ...(1)
∴VC(0−)=VC(0+)=4V
at t=∞, Switch is at position 2 Vc(∞)=5×2=10V ...(2)