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Question
The system 2x+3y+z=5,3x+y+5z=7,x+4y−2z=3 has:
The system 2x+3y+z=5,3x+y+5z=7,x+4y−2z=3 has:
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Solution
The correct option is C no solution
Using Cramer's rule, D=∣∣
∣∣23131514−2∣∣
∣∣=2(−2−20)−3(−6−5)+1(12−1)=−44+33+11=0Since D=0, we cannot have a solution to the given set of equations.
Using Cramer's rule, D=∣∣ ∣∣23131514−2∣∣ ∣∣=2(−2−20)−3(−6−5)+1(12−1)=−44+33+11=0
Since D=0, we cannot have a solution to the given set of equations.
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