The system 2x+3y+z=5,3x+y+5z=7,x+4y-2z=3 has

Unique solution

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Finite number of solutions

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Infinite solutions

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No solutions

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Solution

The correct option is D No solutions
$R a n k o [A] \neq R a n k o f [A B]$
$∴ N o s o l u t i o n .$

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Similar questions

x + 4 y - 2 z = 3, 3 x + y + 5 z = 7

2 x + 3 y + z = 5

x + 4 y - 2 z = 3

3 x + y + 5 z = 7

2 x + 3 y + z = 5

x + 4 y - 2 z = 3

3 x + y + 5 z = 7

2 x + 3 y + z = 5

x + 4 y - 2 z = 3

3 x + y + 5 z = 7

2 x + 3 y + z = 5

2 x + y - z = 7

x - 3 y + 2 z = 1

x + 4 y - 3 z = 5

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