The system of equation 3x-4y=12 and 6x-8y=48

2 solution

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1 solution

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infinite number of solutions

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no solutuion

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Solution

The correct option is D no solutuion
$3 x - 4 y = 12$
here $a_{1} = 3, b_{1} = - 4, c_{1} = 12$
$6 x - 8 y = 48$
here $a_{2} = 6, b_{2} = - 8, c_{2} = 48$
Since
$\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}$
$∴$ It has no solution

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