The system of equations x+2y−3z=0,2x−y+2z=0,x+7y−11z=0 has ⋯⋯ solutions
A
unique
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B
two
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C
0
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D
infinite
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Solution
The correct option is C infinite The given system of equations can be written as AX=O where A=⎡⎢⎣12−32−1217−11⎤⎥⎦, X=⎡⎢⎣xyz⎤⎥⎦,O=⎡⎢⎣000⎤⎥⎦ Here, |A|=∣∣
∣∣12−32−1217−11∣∣
∣∣ |A|=−3+48−45=0 A is singular. So,the system has infinitely many solution