The system of equations x+2y+3z=4 2x+3y+4z=5 3x+4y+5z=6 has
A
Many solutions
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B
No solutions
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C
Unique solution
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D
None of these
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Solution
The correct option is D Many solutions ⎡⎢⎣123235344⎤⎥⎦⎡⎢⎣xyz⎤⎥⎦=⎡⎢⎣456⎤⎥⎦Usingrowtransformation,R3⟶R3−(R1+R2)A=⎡⎢⎣1232340−1−2⎤⎥⎦R2⟶R2−2R1A=⎡⎢⎣1230−1−20−1−2⎤⎥⎦R3⟶R3−R2A=⎡⎢⎣1230−1−2000⎤⎥⎦|A|=0⇒Infinitelymanysolutionsexists