The correct option is A k=3,m≠45
Δ=∣∣
∣∣3−2−k2−4−212−1∣∣
∣∣=0
⇒3(4+4)+2(−2+2)−k(4+4)=0
⇒k=3
Δx=∣∣
∣∣10−2−36−4−25m2−1∣∣
∣∣≠0
⇒10(4+4)+2(−6+10m)−3(12+20m)≠0
⇒m≠45
Δy=∣∣
∣∣310−326−215m−1∣∣
∣∣≠0
⇒3(−6+10m)−10(−2+2)−3(10m−6)≠0
⇒0
Δz=∣∣
∣∣3−2102−46125m∣∣
∣∣≠0
⇒3(−20m−12)+2(10m−6)+10(4+4)≠0
⇒m≠45