wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The system shown in the figure is


A
Stable
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Unstable
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
conditionally stable
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
stable for input u1, but unstable for input u2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D stable for input u1, but unstable for input u2

(T/F)1=(s1)s+21+(s1)(s+2)×1(s1)=(s1)(s+3)

pole is in LHS of s-plane, hence stable.


(T/F)2=1(s1)1+1(s1)×(s1)(s+2)=s+2(s1)(s+3)

Hence unstable as it has pole at right hand side of s-plane.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction to Stability
CONTROL SYSTEMS
Watch in App
Join BYJU'S Learning Program
CrossIcon